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NEET Sample Paper NEET Sample Test Paper-43

  • question_answer
    Along a stretched string equation of transverse wave is y = 3 sin \[\left[ 2\pi \left( \frac{x}{20}-\frac{t}{0.01} \right) \right]\]where, x, y are in cm and t is in sec. The wave velocity is -

    A) 20m/s                           

    B) 30m/s

    C) 15m/s                           

    D) 25m/s

    Correct Answer: A

    Solution :

    Let wave velocity = v \[v=\lambda f\] The given equation of wave \[y=3\,\sin \,\left[ 2\pi \left( \frac{x}{20}-\frac{t}{0.01} \right) \right]\] Compare the given equation with standard equation \[y=A\,\,\sin \left[ 2\pi \left( \frac{x}{\lambda }-\frac{t}{T} \right) \right]\] We get,   A = 3 cm \[\lambda =20cm\] \[f=\frac{1}{T}=100\,Hz\] \[\therefore \,\,\,v=\lambda f=\frac{20\times 100}{100}=20\,m/s\]


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