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NEET Sample Paper NEET Sample Test Paper-43

  • question_answer
    An electron in hydrogen like atom makes a transition from nth orbit and emits radiation corresponding to lyman series. If de-Broglie wavelength of electron in nth orbit is equal to the wavelength of radiation emitted, find the value of n. The atomic number of atoms is 11.

    A) 22

    B)                                       23

    C) 24                                

    D) 25

    Correct Answer: D

    Solution :

    \[2\pi {{r}_{n}}=n\lambda \] \[\frac{1}{\lambda }=\frac{n}{2\pi {{r}_{n}}}=\frac{m{{e}^{2}}z}{2{{\varepsilon }_{0}}{{h}^{2}}n}\]                ?.. (i) Also, for lyman series, \[\frac{1}{\lambda }=R{{z}^{2}}\left[ \frac{1}{{{1}^{2}}}-\frac{1}{{{n}^{2}}} \right]\]                 ?..(ii) From eq. (i) and (ii), n=25


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