A) 36 ATP molecules
B) 40ATP moleules
C) 3 ATP molecules
D) 15 ATP molecules
Correct Answer: A
Solution :
Bioenergetics of glucose oxidation It is a hypothetical, principle based calculation Glycolysis \[-\text{ }2\text{ }NAD{{H}_{2}}\text{ }=\text{ }4/6\text{ }ATP\](via ETS) 6 ATP will be produced if glycolytic \[NAD{{H}_{2}}\] terminally oxidized via malate as partrate shuttle 4 ATP will be produced if glycolytic \[NAD{{H}_{2}}\] terminally oxidized via Glycerol phosphate shuttle 4 ATP produced by substrate level phosphorylation during glycolysis but 2 ATP consumed so \[4-2=2\text{ }by\text{ }\left( SLP \right)\text{ }\text{ }or\text{ }\text{ }ATP\] 2 turns of link reaction \[2\text{ }NAD{{H}_{2}}=\text{ }ATP\text{ }\left( via\left( ETS \right) \right)\] 2 turns of kreb?s reaction \[6\text{ }NAD{{H}_{2}}=18\text{ }ATP\left( via\left( ETS \right) \right)\] \[2\text{ }FAD{{H}_{2}}\text{ }=4\text{ }ATP\left( via\left( ETS \right) \right)\] By substrate level phosphorylation \[2\text{ }ATP=\] So total ATP glycolysis + link Rxn + Kreb?s cycle \[6/8+6+24\,\,ATP\,or\,\,ATP\]
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