NEET Sample Paper NEET Sample Test Paper-42

  • question_answer
    The de-droglie wavelength of an electron in 4th orbit is:

    A) \[2\pi r\]                        

    B) \[4\pi r\]   

    C) \[8\pi r\]                        

    D) \[16\pi r\]

    Correct Answer: C

    Solution :

    de Broglie wavelength  \[\lambda =\frac{h}{P}=\frac{h}{mv}\]                         .?.(1) Multiply and divide RHS of equation (1) by r \[\operatorname{mvr}=\frac{nh}{2\pi }\]                         ?..(2) \[\lambda =\frac{h}{mvr}\times r=\frac{h}{P}\times 2\pi =\frac{2\pi r}{n}\]use equation (2) \[\lambda =\frac{2\pi \times {{\operatorname{n}}^{2}}r}{n}\therefore \operatorname{R}=\frac{{{n}_{2}}{{r}_{o}}}{\operatorname{z}}\] \[\lambda =2\pi \operatorname{nr}\] \[\lambda \left( \operatorname{n}=4 \right)=8\pi \operatorname{r}\]


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