A) \[{{\operatorname{BF}}_{3}}\]
B) \[{{\operatorname{BCL}}_{3}}\]
C) \[{{\operatorname{BBr}}_{3}}\]
D) \[{{\operatorname{BH}}_{3}}\]
Correct Answer: D
Solution :
\[{{\operatorname{BH}}_{3}}\]does not exist in free state. Due to absence of lone pair of electrons on H-atom, this compensation does not occur in\[{{\operatorname{BH}}_{3}}\]. In other words, electron deficiency of B stays and hence to reduce its electron deficiency, \[{{\operatorname{BH}}_{3}}\] dime rises to form\[{{\operatorname{B}}_{3}}{{H}_{6}}\].
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