question_answer

\[{{\operatorname{C}}_{6}}{{H}_{5}}CONHC{{H}_{3}}\]can be converted into \[{{\operatorname{C}}_{6}}{{H}_{5}}C{{H}_{2}}NHC{{H}_{3}}\]by:

A) \[{{\operatorname{NaBH}}_{4}}\]                     

B) \[{{\operatorname{H}}_{2}}-Pd/C\]

C) \[{{\operatorname{LiAlH}}_{4}}\]                     

D) \[\operatorname{Zn}-Hg/HCl\]

Correct Answer: C

Solution :

It is the reduction of amides by reduction with lithium aluminium hydride\[\left( LiAl{{H}_{4}} \right)\].