question_answer

A plot of log Vm versus log p for the adsorption of a gas on a solid gives a straight line with slope equal to:

A) \[\frac{1}{n}\]                          

B) log k     

C) -log k                

D) n

Correct Answer: A

Solution :

\[\frac{x}{m}\]Mass of solute adsorbed per gram of adsorbent C = concentrate on of solute \[\frac{x}{m}=K{{C}^{1/n}}\] Taking log both sides \[\log \frac{1}{m}=log\,K+\frac{1}{n}log\,C\Rightarrow slope=\frac{1}{n}\]