NEET Sample Paper NEET Sample Test Paper-41

  • question_answer
    De-Broglie wavelength of a neutron at \[927{}^\circ C\]is \[\lambda \]. What will be its wavelength at\[27{}^\circ C\]?

    A) \[\frac{\lambda }{9}\]                            

    B) \[\lambda \]

    C) \[2\lambda \]                             

    D) \[4\lambda \]

    Correct Answer: C

    Solution :

    de broglie wavelength solution \[\lambda =\frac{h}{\sqrt{3mKT}}\] \[{{\operatorname{T}}_{1}}=927+273=1200K\] \[{{\operatorname{T}}_{2}}=273+27=300K\] \[{{\lambda }_{1}}=\frac{h}{\sqrt{3mk\times 1200}}\] \[{{\lambda }_{1}}=\frac{h}{\sqrt{3mk\times 300}}\] \[\frac{{{\lambda }_{1}}}{\lambda }=\frac{1}{2}={{\lambda }_{1}}=2\lambda \]


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