NEET Sample Paper NEET Sample Test Paper-41

  • question_answer
    The rate constant K, for the reaction \[{{N}_{2}}{{O}_{5}}\text{ }\left( g \right)\to 2N{{O}_{2}}\left( g \right)+~{{0}_{2}}\left( g \right)\text{ }is\text{ }1.2\times l{{0}^{-2}}\text{ }{{S}^{-1}}.\]Which equation given below describes the change of \[\left[ {{N}_{2}}{{O}_{5}} \right]\] with time? \[{{\left[ {{N}_{2}}{{O}_{5}} \right]}_{0}}\] and \[{{\left[ {{N}_{2}}{{O}_{5}} \right]}_{t}}\] correspond to the concentration of \[{{N}_{2}}{{O}_{5}}\]cinitially and at time t:

    A) \[{{\left[ {{N}_{2}}{{O}_{5}} \right]}_{t}}={{\left[ {{N}_{2}}{{O}_{5}} \right]}_{0}}+kt\]

    B) \[\left[ {{N}_{2}}{{O}_{5}} \right]o={{\left[ {{N}_{2}}{{O}_{5}} \right]}_{t}}{{e}^{kt}}\]

    C) \[log{{\left[ {{N}_{2}}{{O}_{5}} \right]}_{t}}=log{{\left[ {{N}_{2}}{{O}_{5}} \right]}_{o}}+kt\]

    D) \[In\,\,\frac{{{\left[ {{N}_{2}}{{O}_{5}} \right]}_{o}}}{{{\left[ {{N}_{2}}{{O}_{5}} \right]}_{t}}}=kt\]

    Correct Answer: D

    Solution :

    \[\operatorname{In}=\frac{{{\left[ {{N}_{2}}{{O}_{5}} \right]}_{o}}}{{{\left[ {{N}_{2}}{{O}_{5}} \right]}_{T}}}=kt\] \[\operatorname{k}=\frac{1}{t}In\frac{a}{a-x}\] \[=\frac{1}{t}In\frac{{{C}_{o}}}{{{C}_{t}}}\]   \[=\frac{1}{t}\operatorname{In}\frac{{{\left[ {{N}_{2}}{{O}_{5}} \right]}_{o}}}{{{\left[ {{N}_{2}}{{O}_{5}} \right]}_{T}}}\] k is the rate constant.


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