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NEET Sample Paper NEET Sample Test Paper-41

  • question_answer
    Colloidal silver is obtained by reduction of silver nitrate \[\left( AgN{{O}_{3}} \right)\] with:

    A) Acetic acid

    B) Glucose

    C) Molecular hydrogen

    D) Fructose

    Correct Answer: B

    Solution :

    Because glucose has free - CHO group. Hence, it has reducing power, and it is a reducing sugar. It can reduce silver nitrate to form silver (tollen's reagent). We can write the reaction as follow's. \[2AgN{{O}_{3}} + R-CHO+2NaOH=2Ag+R-\] \[\operatorname{COOH}+ 2NaN{{0}_{3}}+{{H}_{2}}0\] Where R - CHO is glucose.


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