A) 0.5
B) 1
C) 2
D) O
Correct Answer: C
Solution :
\[{{\operatorname{t}}_{1/2}}\propto \frac{1}{{{\left[ {{A}_{o}} \right]}^{\operatorname{n}-1}}},\frac{{{\left( {{\operatorname{t}}_{1/2}} \right)}_{1}}}{{{\left( {{\operatorname{t}}_{1/2}} \right)}_{2}}}\] \[{{\operatorname{t}}_{1/2}}=\frac{{{\left[ {{A}_{o}} \right]}_{2}}^{\operatorname{n}-1}}{{{\left[ {{A}_{o}} \right]}_{1}}^{\operatorname{n}-1}}\]c \[={{\left\{ \frac{{{\left[ {{A}_{o}} \right]}_{2}}}{{{\left[ {{A}_{o}} \right]}_{1}}} \right\}}^{\operatorname{n}-1}}\] \[=\frac{t}{t/2}={{\left( \frac{2a}{a} \right)}^{\operatorname{n}-1}}\] \[\operatorname{i}.e {{2}^{1}}={{2}^{n-1}}\] \[\Rightarrow \operatorname{n}-1=1\] \[\operatorname{n}=2\]
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