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NEET Sample Paper NEET Sample Test Paper-41

  • question_answer
    A compound x\[\left( {{C}_{5}}{{H}_{8}} \right)\] reacts with ammonical \[{{\operatorname{AgNO}}_{3}}\]to give a white precipitate, and an oxidation with hot alkaline \[{{\operatorname{KMnO}}_{4}}\]gives the acid, \[{{(C{{H}_{3}})}_{2}}\]CHCOOH. Therefore X is:

    A) \[{{\operatorname{CH}}_{2}}=CHCH=CHC{{H}_{3}}\]

    B) \[C{{H}_{3}}{{\left( C{{H}_{2}} \right)}_{2}}C=CH\]

    C) \[{{\left( C{{H}_{3}} \right)}_{2}}CH-C=C{{H}_{2}}\]

    D) \[{{\left( C{{H}_{2}} \right)}_{2}}CH-C=CH\]

    Correct Answer: D

    Solution :

    As terminal alkyne containing \[{{\left( C{{H}_{3}} \right)}_{2}}CH\] group when this compound goes on oxidation with \[{{\operatorname{KMnO}}_{4}},\]it will give carboxylic acid.        \[\]


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