A) Iso-octane
B) n - octane
C) 2, 2, 3, 3 - tetramethylbutane
D) n - butane
Correct Answer: B
Solution :
\[{{\operatorname{CH}}_{3}}-C{{H}_{2}}-C{{H}_{2}}-C{{H}_{2}}-C{{H}_{2}}-C{{H}_{2}}-C{{H}_{2}}-C{{H}_{3}}\]N - butane \[{{\operatorname{CH}}_{3}}-C{{H}_{2}}-C{{H}_{2}}-C{{H}_{3}}\] And 2, 2, 3, 3 - tetra methyl butane and isooctane are branched in structure. \[\therefore n - octane has high B.P.\] Because: The boiling points of straight chain alkanes increase fairly regularly with increased in their molecular mass. Further, greater the branching, lower the boiling point.
You need to login to perform this action.
You will be redirected in
3 sec
