A) \[1\times {{10}^{23}}\]
B) \[2\times {{10}^{23}}\]
C) \[4\times {{10}^{23}}\]
D) \[6\times {{10}^{23}}\]
Correct Answer: D
Solution :
Molecular mass of nitrogen = 214.0 Molecular of hydrogen Total molecular mass of \[N{{H}_{3}} = 17u\] 1 mole of \[N{{H}_{3}}\] molecules = 17 g \[=6.022\times 1{{0}^{23}} molecules of N{{H}_{3}}\] Now 4.25 g of\[N{{H}_{3}}\] contain \[=\frac{6.022\times {{10}^{23}}\times 4.25\times \left( 1+3 \right)}{17}\] \[=6.022\times 1{{0}^{23}} atoms\]
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