A) \[5 m/{{s}^{2}}\]
B) \[2 m/{{s}^{2}}\]
C) \[3.2 m/{{s}^{2}}\]
D) \[4.3 m/{{s}^{2}}\]
Correct Answer: C
Solution :
\[{{\operatorname{a}}_{centripetal}}=\frac{{{V}^{2}}}{r}=\frac{5\times 5}{10}=2.5\,m/{{s}^{2}}\] \[{{\operatorname{a}}_{\operatorname{tangential}}}=2\,m/{{s}^{2}}\] \[{{\operatorname{a}}_{net}}=\sqrt{{{a}_{c}}^{2}+{{a}_{\operatorname{t}}}^{2}}\] \[=\sqrt{{{\left( 2.5 \right)}^{2}}+{{\left( 2 \right)}^{2}}}\] \[{{\operatorname{a}}_{net}}=3.2m/{{s}^{2}}\]
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