A) 200V, 1A
B) 800V, 2A
C) 100V, 2A
D) 220V, 2.2A
Correct Answer: D
Solution :
\[{{\operatorname{V}}_{z}}=\sqrt{{{V}^{2}}_{R}+{{\left( {{V}_{L}}-{{V}_{C}} \right)}^{2}}}\] \[{{\operatorname{V}}_{z}}=\sqrt{{{V}^{2}}+{{\left( 300-300 \right)}^{2}}}\] \[{{\operatorname{V}}_{z}}=V\] \[\operatorname{V}=220V\] \[{{\operatorname{V}}_{z}}=220V\] \[{{\operatorname{I}}_{ammeter}}=\frac{{{V}_{R}}}{R}=\frac{220}{100}=2.2\,A\]
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