NEET Sample Paper NEET Sample Test Paper-41

  • question_answer
    A npn transistor is connected in common emitter configuration in a given amplifier. A load resistance of \[800\Omega \]is connected in the collector circuit and the voltage drop across it is 0.8V. If the current amplification factor is 0.96 and the input resistance of the circuit is \[192\Omega \], the voltage gain and the power gain of the amplifier will respectively by:

    A) 4, 3.84                         

    B) 3.69, 3.84   

    C) 4, 4                  

    D) 4, 3.69

    Correct Answer: A

    Solution :

    \[{{\operatorname{R}}_{o}}=800\Omega {{\operatorname{V}}_{o}}=0.8V\] \[\beta =0.96{{\operatorname{R}}_{1}}=192\Omega \] \[\Delta {{\operatorname{V}}_{o}}=\Delta {{\operatorname{I}}_{c}}\times {{R}_{o}}\] \[\Delta {{\operatorname{I}}_{c}}=\frac{0.8}{800}=1mA\] \[\operatorname{Voltage} gain {{A}_{v}}=\beta \frac{{{R}_{o}}}{{{R}_{1}}}=\frac{0.96\times 800}{192}=4\] \[\operatorname{Power} gain ={{\beta }^{2}}\frac{{{R}_{o}}}{{{R}_{1}}}=\frac{0.96\times 0.96\times 800}{192}=3.84\]


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