A) \[\operatorname{hc}({{\lambda }_{\operatorname{o}}}-\lambda )\]
B) \[\frac{\operatorname{hc}}{{{\lambda }_{\operatorname{o}}}-\lambda }\]
C) \[\frac{h}{c}\left[ \frac{{{\lambda }_{\operatorname{o}}}-\lambda }{\lambda {{\lambda }_{\operatorname{o}}}} \right]\]
D) \[\operatorname{hc}\left[ \frac{{{\lambda }_{\operatorname{o}}}-\lambda }{\lambda {{\lambda }_{\operatorname{o}}}} \right]\]
Correct Answer: D
Solution :
equation for photoelectric effect \[\operatorname{W}={{W}_{o}}+K.E\] \[\frac{hc}{\lambda }=\frac{hc}{{{\lambda }_{o}}}+K.E\] \[K.E=\frac{hc}{\lambda }=\frac{hc}{{{\lambda }_{o}}}\Rightarrow hc\left[ \frac{1}{\lambda }-\frac{1}{{{\lambda }_{o}}} \right]\] \[K.E=hc\left[ \frac{{{\lambda }_{o}}-\lambda }{\lambda {{\lambda }_{o}}} \right]\]
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