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NEET Sample Paper NEET Sample Test Paper-40

  • question_answer
    Enthalpy of\[C{{H}_{4}}+\frac{1}{2}{{O}_{2}}\xrightarrow{{}}C{{H}_{3}}OH\]is negative. If enthalpy of combustion of \[C{{H}_{4}}\]and \[C{{H}_{3}}OH\]are\[x\]and y respectively, then which relation is correct?

    A) \[x>y\]

    B) \[x<y\]

    C) \[x=y\]

    D) \[x\ge y\] 

    Correct Answer: A

    Solution :

     \[C{{H}_{4}}(g)+\frac{1}{2}{{O}_{2}}(g)\xrightarrow{{}}C{{H}_{3}}OH(l)\] \[\therefore \]\[\Delta \Eta =-\][\[\Delta \Eta \]of combustion of\[C{{H}_{3}}OH-\](\[\Delta \Eta \]of combustion of\[C{{H}_{4}}\])] \[=-[(-y)-(-x)]=-[-y+x]=y-x\] \[\therefore \]\[x<y.\]


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