A) 0.0354
B) 0.0177
C) 0.177
D) 1.770
Correct Answer: B
Solution :
1.00 m solution means 1 mole solute is present in 1000 g water. \[{{n}_{{{H}_{2}}O}}=\frac{1000}{18}=55.5\,mol\,{{H}_{2}}O\] \[{{X}_{solute}}=\frac{{{n}_{solute}}}{{{n}_{solute}}+{{n}_{{{H}_{2}}O}}}=\frac{1}{1+55.5}=0.0177\]
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