A)
B)
C)
D)
Correct Answer: C
Solution :
\[Br-\overset{3}{\mathop{C}}\,{{H}_{2}}-\overset{2}{\mathop{C}}\,H=\overset{1}{\mathop{C}}\,{{H}_{2}}\]is 3-bromo-prop-l-ene. As bromo is treated as substituent. Hence, while numbering double bond should get preference.
You need to login to perform this action.
You will be redirected in
3 sec
