A) \[-82\,kJ\,mo{{l}^{-1}}\]
B) \[-41\,kJ\,mo{{l}^{-1}}\]
C) \[-1312\,kJ\,mo{{l}^{-1}}\]
D) \[-164\,kJ\,mo{{l}^{-}}\]
Correct Answer: A
Solution :
The energy of second Bohr orbit of hydrogen atom\[({{E}_{2}})\]is \[-328\,kJ\,mo{{l}^{-1}}\] Because, \[{{E}_{2}}=\frac{-1312}{{{2}^{2}}}\,kJ\,mo{{l}^{-1}}\] \[\therefore \]\[{{E}_{n}}=\frac{-1312}{{{n}^{2}}}\,kJ\,mo{{l}^{-1}}\] (if\[n=4\]) \[\therefore \] \[{{E}_{4}}=\frac{-1312}{{{4}^{2}}}=-82\,kJ\,mo{{l}^{-1}}\]
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