• # question_answer In the following reaction, ${{C}_{6}}{{H}_{5}}C{{H}_{2}}Br$ $\xrightarrow[2.{{H}_{3}}{{O}^{+}}]{1\,Mg.\,Ether}X,$the product ?X? is A) ${{C}_{6}}{{H}_{5}}C{{H}_{2}}C{{H}_{2}}{{C}_{6}}{{H}_{5}}$B) ${{C}_{6}}{{H}_{5}}C{{H}_{2}}OC{{H}_{2}}{{C}_{6}}{{H}_{5}}$C) ${{C}_{6}}{{H}_{5}}C{{H}_{2}}OH$D) ${{C}_{6}}{{H}_{5}}C{{H}_{3}}$

${{C}_{6}}{{H}_{5}}C{{H}_{2}}Br+Mg\xrightarrow{ether}{{C}_{6}}{{H}_{5}}C{{H}_{2}}MgBr$(in ether as solution)  ${{C}_{6}}{{H}_{5}}C{{H}_{2}}$ $MgBr\xrightarrow{{{H}^{+}}}{{C}_{6}}{{H}_{5}}C{{H}_{3}}+MgBr(OH)$ H OH