| (i)\[{{E}_{cell}}={{E}_{OP}}\]anode\[-{{E}_{RP}}\]cathode |
| (ii)\[{{E}_{cell}}={{E}_{OP}}\]anode\[+{{E}_{RP}}\]cathode |
| (iii)\[{{E}_{cell}}={{E}_{RP}}\]anode\[+{{E}_{RP}}\]cathode |
| (iv)\[{{E}_{cell}}={{E}_{OP}}\]anode\[-{{E}_{OP}}\]cathode |
A) (iii) and (i)
B) (i) and (ii)
C) (iii) and (iv)
D) (ii) and (iv)
Correct Answer: D
Solution :
\[{{E}_{cell}}={{E}_{Opanode}}+{{E}_{RPCathode}}={{E}_{OPanode}}-{{E}_{OPcathode}}\]
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