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NEET Sample Paper NEET Sample Test Paper-37

  • question_answer
    The oxidation states of sulphur in the anions \[SO_{3}^{2-},{{S}_{2}}O_{4}^{2-}\] and \[{{S}_{2}}O_{6}^{2-}\]follow the order

    A) \[{{S}_{2}}O_{4}^{2-}<SO_{3}^{2-}<{{S}_{2}}O_{6}^{2-}\]

    B) \[SO_{3}^{2-}<{{S}_{2}}O_{4}^{2-}<{{S}_{2}}O_{6}^{2-}\]

    C) \[{{S}_{2}}O_{4}^{2-}<{{S}_{2}}O_{6}^{2-}<SO_{3}^{2-}\]

    D) \[{{S}_{2}}O_{6}^{2-}<{{S}_{2}}O_{4}^{2-}<SO_{3}^{2-}\]    

    Correct Answer: A

    Solution :

     S in \[{{S}_{2}}O_{4}^{2-},SO_{3}^{2-}\]and \[{{S}_{2}}O_{6}^{2-}\]has \[+3,\,+4\,\]and \[+5\] oxidation numbers.


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