A) \[M{{e}_{2}}SiC{{l}_{2}}\]
B) \[M{{e}_{3}}SiCl\]
C) \[PhSiC{{l}_{3}}\]
D) \[MeSiC{{l}_{3}}\]
Correct Answer: B
Solution :
\[M{{e}_{3}}SiCl\] on hydrolysis forms a dimer \[M{{e}_{3}}SiCl+HOH\xrightarrow{{}}M{{e}_{3}}SiOH+HCl\] \[M{{e}_{3}}SiCl+HOSiM{{e}_{3}}\xrightarrow{{}}M{{e}_{3}}Si-O-SiM{{e}_{3}}\]
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