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NEET Sample Paper NEET Sample Test Paper-35

  • question_answer
    \[C{{H}_{3}}N{{H}_{2}}\](\[0.1\] mole,\[{{K}_{b}}=5\times {{10}^{-4}}\]) is added to \[0.08\] moles of \[HCl\]and the solution is diluted to one litre, resulting hydrogen ion concentration is

    A)  \[1.6\times {{10}^{-11}}\]         

    B)  \[8\times {{10}^{-11}}\]

    C) \[5\times {{10}^{-5}}\]           

    D)  \[8\times {{10}^{-2}}\]

    Correct Answer: B

    Solution :

    \[C{{H}_{3}}N{{H}_{2}}\] + \[HCl\] \[\to \] \[C{{H}_{3}}NH_{3}^{+}\] + \[C{{l}^{-}}\]
    Initial \[0.10\] \[0.08\] \[0\] \[0\]
    Final \[0.02\] \[0\] \[0.08\] \[0.08\]
    \[pOH=p{{K}_{b}}+\log \frac{[C{{H}_{3}}NH_{3}^{+}]}{[C{{H}_{3}}N{{H}_{2}}]}\] \[pOH=-\log (5\times {{10}^{-4}})+\log \frac{0.08}{0.02}=3.9\] \[pH=14-pOH=14-3.9=10.1\] \[[{{H}^{+}}]=8\times {{10}^{-11}}\]


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