• # question_answer A couple of ${{10}^{5}}N-m$is applied to a flywheel of mass 10 kg and radius of gyration 50m. Then the angular acceleration of the wheel is (in$rad/{{s}^{2}}$) A)  200               B)  50C)  10                D)  4

Angular acceleration is $\alpha =\frac{\tau }{I}=\frac{\tau }{M{{K}^{2}}}=\frac{{{10}^{5}}}{10\times {{50}^{2}}}=4\frac{rad}{{{s}^{2}}}$