NEET Sample Paper NEET Sample Test Paper-34

  • question_answer The period of oscillation of a ring oscillating about an axis passing throngs its rim is 1 second If \[g={{\pi }^{2}},\]then the length of the equivalent simple pendulum will be:-

    A)  \[0.25\,m\]

    B)  \[0.5\text{ }m\]

    C)  \[0.75\text{ }m\]            

    D)  \[\text{1}\text{.0 }m\]

    Correct Answer: A

    Solution :

    \[T=2\pi \sqrt{\frac{L}{g}}\,\,\,\Rightarrow \,\,1=2\pi \sqrt{\frac{L}{{{\pi }^{2}}}}\Rightarrow L=\frac{1}{4}m\]

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