• question_answer The period of oscillation of a ring oscillating about an axis passing throngs its rim is 1 second If $g={{\pi }^{2}},$then the length of the equivalent simple pendulum will be:- A)  $0.25\,m$B)  $0.5\text{ }m$C)  $0.75\text{ }m$            D)  $\text{1}\text{.0 }m$

$T=2\pi \sqrt{\frac{L}{g}}\,\,\,\Rightarrow \,\,1=2\pi \sqrt{\frac{L}{{{\pi }^{2}}}}\Rightarrow L=\frac{1}{4}m$