question_answer

When two different materials A and B having atomic number \[{{Z}_{1}}\] and \[{{Z}_{2}},\] are used as the target in coolidge x-ray tube at different operating voltages \[{{V}_{1}}\] and \[{{V}_{2}}\]respectively their spectrums are found as below: The correct relation is:-

A)  \[{{V}_{1}}>{{V}_{2}}\]and \[{{Z}_{1}}>{{Z}_{2}}\]

B)  \[{{V}_{1}}<{{V}_{2}}\] and \[{{Z}_{1}}<{{Z}_{2}}\]

C)  \[{{V}_{1}}<{{V}_{2}}\] and \[{{Z}_{1}}>{{Z}_{2}}\]

D)  \[{{V}_{1}}>{{V}_{2}}\] and \[{{Z}_{1}}<{{Z}_{2}}\]