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NEET Sample Paper NEET Sample Test Paper-31

  • question_answer
    A bulb (100W, 200V) is attached to a voltage of 160 V. The power dissipation is :-

    A)  64W              

    B)  100W

    C)  32W              

    D)  50W

    Correct Answer: A

    Solution :

    \[P={{\left( \frac{{{V}_{S}}}{{{V}_{P}}} \right)}^{2}}W={{\left( \frac{160}{200} \right)}^{2}}100=64\,W\]


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