A) \[0.54\,V\]
B) \[-0.54\,V\]
C) \[0.18\,V\]
D) \[-0.18\,V\]
Correct Answer: A
Solution :
In the given reaction \[{{I}^{-}}\] has been oxidized to \[{{I}_{2}}\] and \[C{{r}_{2}}O_{7}^{2-}\] has been reduced to \[C{{r}^{3+}}\] \[_{E_{cell}^{o}}=E_{C{{r}_{2}}O_{7}^{2-}}^{o}-E_{{{I}_{2}}}^{o}\] \[0.79=1.33-E_{{{I}_{2}}}^{o}\] \[E_{{{I}_{2}}}^{o}=0.54\,V\]You need to login to perform this action.
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