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NEET Sample Paper NEET Sample Test Paper-2

  • question_answer
    If the binding energy per nucleon in \[_{3}^{7}Li\] and \[2_{2}^{4}He\] nuclei are \[5.60\text{ }MeV\] and \[7.06\text{ }MeV\]respectively, then in the reaction \[_{1}^{1}H+_{3}^{7}Li\to 2_{2}^{4}He,\]energy of proton must be:

    A)  \[39.2\text{ }MeV\]         

    B)  \[28.24\text{ }MeV\]

    C)  \[17.28\text{ }MeV\]       

    D)  \[1.46\text{ }MeV\]

    Correct Answer: C

    Solution :

    Here, \[{{\varepsilon }_{p}}\]energy of Photon will be \[{{\varepsilon }_{p}}=(8\times 7.06-7\times 5.60)MeV=17.28\,MeV\]


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