A) \[3\times {{10}^{-10}}kg\,\,m{{s}^{-1}}\]
B) \[{{10}^{-10}}kg\,\,m{{s}^{-1}}\]
C) \[8\times {{10}^{-10}}kg\,\,m{{s}^{-1}}\]
D) \[2\times {{10}^{-10}}kg\,\,m{{s}^{-1}}\]
Correct Answer: D
Solution :
From formula Impulse = change in momentum. Also, momentum of incident photon is given by \[p=\frac{h}{\lambda }\] A perfect reflection implies the same momentum \[\therefore \] change in momentum is given as, \[\Delta p=p-(-p)=2p=2\left[ \frac{E}{c} \right]\] ?..(i) \[\left( \therefore \,\,E=\frac{hc}{\lambda }=pe \right)\] Here, \[E=3\times {{10}^{-2}}\]Joule Putting the given value in equation (i), we get \[\Delta p=2\times \frac{3\times {{10}^{-2}}}{3\times {{10}^{-8}}}\] \[\Delta p=2\times {{10}^{8}}kg\,m{{s}^{-1}}\]
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