A) acidic nature
B) Covalent nature
C) ionisation property
D) electron deficient nature
Correct Answer: D
Solution :
Boron compounds behave as lewis acid due to their electron deficient nature. They act as electron pair acceptor. \[\underset{Lewis\,\,acid}{\mathop{F-\underset{F}{\mathop{\underset{|}{\mathop{\overset{F}{\mathop{\overset{|}{\mathop{B}}\,}}\,}}\,}}\,}}\,\,\,\,\,+\,\,\,\underset{Lewis\,\,base}{\mathop{\underset{H}{\mathop{\underset{|}{\mathop{\overset{H}{\mathop{\overset{|}{\mathop{N}}\,}}\,}}\,}}\,-H}}\,\xrightarrow{{}}F-\underset{F}{\mathop{\underset{|}{\mathop{\overset{F}{\mathop{\overset{|}{\mathop{B}}\,}}\,}}\,}}\,\xleftarrow[{}]{}\underset{H}{\mathop{\underset{|}{\mathop{\overset{H}{\mathop{\overset{|}{\mathop{N}}\,}}\,}}\,}}\,-H\]
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