A) \[CuS{{O}_{4}}\] reacts with \[KI\] in aqueous solution to give \[C{{u}_{2}}{{I}_{2}}\]
B) \[CuS{{O}_{4}}\] reacts with \[KCl\] in aqueous solution to give \[C{{u}_{2}}C{{l}_{2}}\]
C) \[CuS{{O}_{4}}\] reacts with \[NaOH\] and glucose in aqueous medium to give \[C{{u}_{2}}O\]
D) \[CuS{{O}_{4}}\] on strong heating gives \[CuO\]
Correct Answer: B
Solution :
\[C{{l}^{-}}\] in \[KCl\] is a very weak reducing agent and therefore it cannot reduce \[C{{u}^{2+}}\] to \[C{{u}^{+}}\]Hence, \[CuS{{O}_{4}}\] does not form \[C{{u}_{2}}C{{l}_{2}}\] on reaction with \[KCl\]in aqueous solution.
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