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NEET Sample Paper NEET Sample Test Paper-25

  • question_answer
    If a long spring is stretched by 0.02 m, its potential energy is U. If the spring is stretched by 0.1 m, then its potential energy will be

    A) \[\frac{U}{5}\]                          

    B)  U

    C)  5 U                             

    D)  25 U

    Correct Answer: D

    Solution :

     \[U\propto {{x}^{2}}\] \[\Rightarrow \]\[\frac{{{U}_{2}}}{{{U}_{1}}}={{\left( \frac{{{x}_{2}}}{{{x}_{1}}} \right)}^{2}}={{\left( \frac{0.1}{0.02} \right)}^{2}}=25\]\[\therefore \]\[{{U}_{2}}=25\,U\]


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