A) The electronegativity of F is greater than that of O
B) \[{{H}_{2}}O\]involves hydrogen bonding whereas \[Be{{F}_{2}}\]is a discrete molecule
C) \[{{H}_{2}}O\]is linear and\[Be{{F}_{2}}\]is angular
D) \[{{H}_{2}}O\] is angular and\[Be{{F}_{2}}\]is linear
Correct Answer: D
Solution :
In a linear symmetrical molecule like \[Be{{F}_{2}},\] bond angle between three atoms is\[{{180}^{o}}\], hence the polarity due to one bond is cancelled by the equal polarity due to other bond, while it is not so in the case of angular molecules like\[{{H}_{2}}O.\]
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