A) Cl
B) C
C) S
D) H
Correct Answer: A
Solution :
\[\overset{+1}{\mathop{K}}\,\overset{+5}{\mathop{Cl}}\,\overset{-2}{\mathop{{{O}_{3}}}}\,+\overset{+1}{\mathop{{{H}_{2}}}}\,\overset{+3}{\mathop{{{C}_{2}}}}\,\overset{-2}{\mathop{{{O}_{4}}}}\,+\overset{+1}{\mathop{{{H}_{2}}}}\,\overset{+6-2}{\mathop{{{S}_{2}}}}\,{{O}_{4}}\xrightarrow{{}}\]? \[{{\overset{+1}{\mathop{K}}\,}_{2}}\overset{+6}{\mathop{S}}\,{{\overset{-2}{\mathop{O}}\,}_{4}}+\overset{+1}{\mathop{K}}\,\overset{-1}{\mathop{Cl}}\,+\overset{+4}{\mathop{C}}\,{{\overset{-2}{\mathop{O}}\,}_{2}}+{{\overset{+1}{\mathop{H}}\,}_{2}}\overset{-2}{\mathop{O}}\,\] \[\therefore \]Cl is the element which undergoes maximum change in the oxidation state.
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