NEET Sample Paper NEET Sample Test Paper-24

  • question_answer
    A bubble of air is underwater at temperature \[{{15}^{o}}C\] and the pressure 1.5 bar. If the bubble rises to the surface where the temperature is \[{{25}^{o}}C\] and the pressure is 1.0 bar, what will happen to the volume of the bubble?

    A)  Volume will become smaller by a factor of 0.70

    B)  Volume will become greater by a factor of 1.1                  

    C)  Volume will become greater by a factor of 1.6

    D)  Volume will become greater by a factor of 2.5

    Correct Answer: C

    Solution :

     Given \[{{P}_{1}}=1.5\,bar;{{T}_{1}}=273+15=288\,K;\,{{V}_{1}}=V\] \[{{P}_{2}}=1.0\,bar;{{T}_{1}}=273+25=298\,K;\,{{V}_{2}}=?\] \[\frac{{{P}_{1}}{{V}_{1}}}{{{T}_{1}}}=\frac{{{P}_{2}}{{V}_{2}}}{{{T}_{2}}}\] \[\frac{1.5\times V}{288}=\frac{1\times {{V}_{2}}}{298}\] \[{{V}_{2}}=1.55\,V,\] i.e., volume of bubble will be almost 1.6 time to initial volume of bubble.


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