A)
B)
C)
D)
Correct Answer: C
Solution :
Let the vertical component of the initial velocity of the projectile be\[{{u}_{y}}.\] \[\therefore \] \[h={{u}_{y}}t-\frac{1}{2}g{{t}^{2}}\] \[\frac{dh}{dt}={{u}_{y}}-gt\] or, \[\frac{{{d}^{2}}h}{d{{t}^{2}}}=-g\] As the second derivative is negative so, h versus t curve is convex upwards. Hence, the correction option is [c].You need to login to perform this action.
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