• # question_answer A speech signal of 3 kHz is used to modulate a carrier signal of frequency 1 MHz, using amplitude modulation. The frequencies of the side bands will be A)  1.003 MHz and 0.997 MHzB)  3001 kHz and 2997 kHzC)  1003 kHz and 1000 kHzD)  1 MHz and 0.997 MHz

Here, $\upsilon =1\,MHz,\,\Delta v=3\,kHz=0.003\,MHz.$ Using amplitude modulation, the frequencies of the side band $=(\upsilon +\Delta v)$and $(\upsilon -\Delta v)$ $=(1+0.003)$and $(1-0.003)$ $=1.003\,MHz$and 0.997 MHz Hence, the correction option is (a).