• # question_answer The angular momentum of an electron in a hydrogen atom is proportional to: A) $\frac{1}{\sqrt{r}}$                          B) $\frac{1}{r}$                        C) $\sqrt{r}$                   D)   ${{r}^{2}}$

Angular Momentum $=L=\frac{nh}{2\pi }$ The radius of the orbit $=r={{a}_{0}}{{n}^{2}}\Rightarrow n=\sqrt{r/{{a}_{0}}}$ Where ${{a}_{0}}=$radius of first orbit of hydrogen atom. $\therefore$    $L=\sqrt{\frac{r}{{{a}_{0}}}}\times \frac{h}{2\pi }\Rightarrow L\alpha \sqrt{r}$ Hence, the correction option is(c).