A) \[{{\lambda }_{1}}={{\lambda }_{2}}\]
B) \[{{\lambda }_{1}}>{{\lambda }_{2}}\]
C) \[{{\lambda }_{1}}<{{\lambda }_{2}}\]
D) \[{{\lambda }_{1}}<{{\lambda }_{2}}\]or\[{{\lambda }_{2}}<{{\lambda }_{1}}\]
Correct Answer: D
Solution :
The work done by magnetic field is zero, so there is no charge in KE and hence no charge in the magnitude of momentum. The de-Broglie wavelength \[{{\lambda }_{2}}\]of electron in magnetic field remains the same. The KE of electron in electric field may increase or decrease depending on the angle between the velocity of electron and the electric field. Accordingly, \[{{\lambda }_{1}}\]may increase or decrease. \[\therefore \] \[{{\lambda }_{1}}<{{\lambda }_{2}}\]or \[{{\lambda }_{2}}<{{\lambda }_{1}}\] Hence, the correction option is (d).You need to login to perform this action.
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