NEET Sample Paper NEET Sample Test Paper-20

  • question_answer
    If 0.1 M of a weak acid is taken and its percentage of degree of ionization is 1.34%, then its ionization  constant will be

    A) \[0.182\times {{10}^{-5}}\]

    B)      \[1.79\times {{10}^{-5}}\]  

    C)      \[0.8\times {{10}^{-5}}\]       

    D)       None of these 

    Correct Answer: B

    Solution :

    As \[{{K}_{a}}=C{{\alpha }^{2}}.\] As, \[C=0.1\,M,\,\alpha =1.34%=0.0134.\] So,\[K\alpha =0.1\times {{(1.34\times {{10}^{-2}})}^{2}}\] \[=1.79\times {{10}^{-5}}\] Hence, the correct option is (b).


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