A) \[\frac{3F}{2MR}\]
B) \[\frac{2F}{3MR}\]
C) \[\frac{F}{2MR}\]
D) \[\frac{3F}{4MR}\]
Correct Answer: B
Solution :
In case of rolling without slipping point of contact P on ground is at rest. Hence the cylinder will rotate about P with angular acceleration: \[\alpha =\frac{{{\tau }_{p}}}{{{I}_{p}}}=\frac{F.R}{\frac{3}{2}M\,{{R}^{2}}}=\frac{2E}{3MR}\] Hence, the correction option is (b).
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