• # question_answer The correct increasing bond angles order is: A)  $B{{F}_{3}}<N{{F}_{3}}<P{{F}_{3}}<Cl{{F}_{3}}$B)  $Cl{{F}_{3}}<P{{F}_{3}}<N{{F}_{3}}<B{{F}_{3}}$C)  $B{{F}_{3}}\approx N{{F}_{3}}<P{{F}_{3}}<Cl{{F}_{3}}$D)  $B{{F}_{3}}<N{{F}_{3}}<P{{F}_{3}}<Cl{{F}_{3}}$

$B{{F}_{3}}$ has $s{{p}^{2}}$ hybridization and ${{120}^{o}}$ bond angle (maximum). Its structure is planar. Higher the electronegativity of central atom (in $s{{p}^{3}}$ hybridized) larger the bond angle but presence of lone pair of electrons decreases the  bond angle. Greater the number of lone pair of electrons lower the bond angle.