A) \[\sqrt{2}\,m/{{s}^{2}}N-W\]
B) \[\frac{1}{2}\,m/{{s}^{2}}\,N-W\]
C) \[\sqrt{2}\,m/{{s}^{2}}\,N-E\]
D) 0
Correct Answer: A
Solution :
Average accelerations\[=\frac{\Delta \vec{v}}{\Delta t}=\frac{|{{{\vec{v}}}_{2}}-{{{\vec{v}}}_{1}}|}{\Delta t}\] \[\therefore \]Magnitude of average acceleration \[=\frac{10\sqrt{2}}{10}=\sqrt{2}\frac{m}{{{s}^{2}}}NW.\] Hence, the correction option is [c].You need to login to perform this action.
You will be redirected in
3 sec