NEET Sample Paper NEET Sample Test Paper-19

  • question_answer If\[{{\lambda }_{1}}\]and\[{{\lambda }_{2}}\]denote the wavelengths of de Broglie waves for electrons in Bohr's first and second orbits in the hydrogen atom, then\[{{\lambda }_{1}}/{{\lambda }_{2}}\]will be:

    A)  2                                

    B) \[\frac{1}{2}\]

    C)  4                                

    D) \[\frac{1}{4}\] 

    Correct Answer: B

    Solution :

    De-Broglie wavelength \[=\lambda =\frac{h}{\rho }\] \[\therefore \]\[\lambda =\frac{h}{\sqrt{2mk}}\Rightarrow \lambda \alpha \frac{1}{\sqrt{k}}\] Where, k is the kinetic energy of the electron. Now \[\lambda =\frac{h}{\sqrt{2mk}}\Rightarrow \lambda \alpha \frac{1}{\sqrt{k}}\] Hence, the correction option is [b].


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