• # question_answer The figure shows a block of mass m kept on inclined plane with inclination $\theta .$ The tension in the string is: A)  8 N                            B)  10 NC)  0.8 N             D)  0

We know $\tan \alpha =0.8$ $\alpha ={{\tan }^{-1}}(0.8)={{39}^{o}}$ The given angle of inclination is less than angle of repose. So, 1 kg block has no tendency to move. Therefore, T=0, Hence, the correction option is [d].